Free UK CAA Part-66 Module 7A Maintenance Practices — B1.1 MCQ Practice Questions

Sample Practice Questions

Try these 10 sample questions from the UK CAA Part-66 Module 7A Maintenance Practices — B1.1 MCQ practice bank. Each includes the answer and explanation. Continue with the interactive practice above to review the full question set.

1. 1A tool draws 8 A through four identical parallel strands at a damaged point in its supply lead. Two strands then break, while total current remains 8 A and the two surviving strands share it equally. What current does each surviving strand carry?

   1. A.2 A
   2. B.4 ACorrect answer: B
   3. C.8 A
   4. D.16 A

   Explanation: The handbook states: "When several wires inside a power cord are broken, the current passing through the remaining wires increases." With two equal surviving paths, current per strand = 8 A ÷ 2 = 4 A, twice the original 8 A ÷ 4 = 2 A. The 2 A distractor uses the original four-strand divisor; 8 A assigns all current to each strand; 16 A multiplies by two instead of dividing. Increased loading of the surviving strands is a fire risk; the damaged lead must be repaired or replaced before further use.

   Reference: FAA-H-8083-30B, Aviation Maintenance Technician Handbook—General — Chapter 1, Safety Around Electricity

2. 2A flush setscrew securing an aircraft access-panel fitting has an internal hexagonal recess. Which tool should the technician use to turn it?

   1. A.Hook spanner
   2. B.Flare-nut wrench
   3. C.Crowfoot wrench
   4. D.Allen wrenchCorrect answer: D

   Explanation: The handbook states: "Most headless setscrews are the hex-head Allen type and must be installed and removed with an Allen wrench." Its hexagonal bar fits the recess. The other named tools engage different external fastener forms.

   Reference: FAA-H-8083-30B, Aviation Maintenance Technician Handbook—General — Chapter 11, Special Wrenches

3. 3A bracket drawing carries several approved changes. The technician needs the date, nature and authorisation of a particular change. Which drawing feature should be consulted?

   1. A.Bill of material
   2. B.Revision blockCorrect answer: B
   3. C.Zone grid
   4. D.Finish mark

   Explanation: The handbook states: "The revision block contains the identification symbol, the date, the nature of the revision, the authority for the change, and the name of the draftsman who made the change." The revision block provides the required change history; the material list, grid and finish indication serve other purposes.

   Reference: FAA-H-8083-30B, Aviation Maintenance Technician Handbook—General — Chapter 4, Revision Block

4. 4A technician checks an isolated wire end-to-end with a serviceable ohmmeter and obtains an infinite-resistance indication. What does this indicate about the wire path?

   1. A.An open circuitCorrect answer: A
   2. B.A sound continuity path
   3. C.A low-resistance bond
   4. D.A shorted conductor path

   Explanation: The handbook states: "If the circuit is open or has a very poor connection at some point like an over-crimped pin in a connector, then the ohmmeter reads infinity or some very high resistance." Infinite resistance indicates the wire path is interrupted or has a very poor connection; the three other conditions would give a low resistance on this isolated end-to-end check.

   Reference: FAA-H-8083-30B, Aviation Maintenance Technician Handbook—General — Chapter 12, Continuity Checks

5. 5Aircraft-type tube-flaring equipment is being selected for a conventional aircraft flared tube connection. Which nominal flare angle falls within the handbook's aircraft-tool range?

   1. A.30°
   2. B.45°
   3. C.37°Correct answer: C
   4. D.60°

   Explanation: The handbook states: "The flaring tool used for aircraft tubing has male and female dies ground to produce a flare of 35° to 37°." A nominal 37° aircraft flare is in the stated range. A 45° automotive flare does not match this aircraft connection; 30° and 60° are also outside the stated aircraft-tool range.

   Reference: FAA-H-8083-30B, Aviation Maintenance Technician Handbook—General — Chapter 9, Tube Flaring

6. 6Why is collective backlash in an aircraft control-surface mechanical linkage checked against the permitted limits?

   1. A.To control the risk of linkage binding.
   2. B.To control the risk of excessive friction.
   3. C.To control the risk of control flutter.Correct answer: C
   4. D.To control the risk of control reversal.

   Explanation: CAP 562 identifies "control flutter" as a possible result of collective backlash caused by linkage slackness. Binding and excessive friction involve resistance to movement; control reversal is a different response problem. The backlash-related oscillation hazard here is flutter.

   Reference: CAP 562, Civil Aircraft Airworthiness Information and Procedures — Book 2, Chapter 20, Leaflet 20-80, §9.8

7. 7A technician must mark an arc on sheet metal in an area that will remain in the finished aircraft part. Which layout tool avoids introducing a scribed stress raiser?

   1. A.Dividers
   2. B.Scriber
   3. C.Prick punch
   4. D.Pencil compassCorrect answer: D

   Explanation: The handbook states: "All other arcs or circles are drawn with pencil compasses to avoid scratching the material." Use the pencil compass for retained surfaces. Dividers and scribers scratch the metal; a prick punch indents it. Marks cut away during fabrication are treated differently.

   Reference: FAA-H-8083-30B, Aviation Maintenance Technician Handbook—General — Chapter 11, Dividers and Pencil Compasses

8. 8For a weight-and-balance calculation, an assembly is represented by 1,000 kg at an arm of +2.00 m and 500 kg at +5.00 m from the same datum. Where is its combined centre of gravity?

   1. A.+3.50 m
   2. B.+4.50 m
   3. C.+1.67 m
   4. D.+3.00 mCorrect answer: D

   Explanation: The handbook states: "The total arm is the airplane CG and is found by dividing the total moment by the total weight." Total moment = (1,000 × 2.00) + (500 × 5.00) = 4,500 kg·m; total mass = 1,500 kg; CG = 4,500/1,500 = +3.00 m. +3.50 averages the arms without weighting; +4.50 divides by only 1,000 kg; +1.67 omits the first moment and rounds 2,500/1,500.

   Reference: FAA-H-8083-30B, Aviation Maintenance Technician Handbook—General — Chapter 6, adverse-loading checks—total arm calculation

9. 9Before performing the general visual stage of a corrosion inspection, what preparation is required for the area being examined?

   1. A.Apply its final protective coating.
   2. B.Proof-load its supporting structure.
   3. C.Perform its final dimensional acceptance.
   4. D.Thoroughly clean the inspection area.Correct answer: D

   Explanation: The handbook states: "All corrosion inspections start with a thorough cleaning of the area to be inspected." Cleaning exposes the surface before general and then detailed visual inspection. Recoating or final dimensional acceptance follows assessment and treatment; proof loading is not the specified preparation.

   Reference: FAA-H-8083-30B, Aviation Maintenance Technician Handbook—General — Chapter 8, Inspection

10. 10In a UK Part-145 maintenance organisation, a removed component has reached its mandatory life limitation. No life extension or approved repair solution applies. Into which category must it be placed?

    1. A.Serviceable component
    2. B.Standard part
    3. C.Unserviceable component awaiting restoration
    4. D.Unsalvageable componentCorrect answer: D

    Explanation: Part-145 identifies "Components categorised as unsalvageable because they have reached their mandatory life limitation or contain a non-repairable defect." A life-expired component without an applicable approved extension belongs in the unsalvageable category, rather than routine unserviceable stock awaiting restoration. It is neither serviceable nor a standard part, and 145.A.42(c)(ii) prevents its re-entry into the supply system under the stated conditions.

    Reference: UK Regulation (EU) No. 1321/2014, CAA consolidated publication — Annex II (Part-145), 145.A.42(a)(iii) and (c)(ii)